The Zetter Bloomsbury is a 4-star hotel in 2-7 Montague Street, London, available to book on JourneyDeal from ₹56,865 per night.
Choose from 2 room option(s) with room only / roomonly plans. Free-cancellation rates are available on select rooms.
For flights, London airport (LCY) sits about 13 km away. It is around 974 m from the middle of our London listings.
Room types include Cosy Courtyard (1 Double Bed) - Package Rate, Cosy Courtyard. A refundable rate is available.
| Room type | Board | Sleeps | Cancellation | Price / night |
|---|---|---|---|---|
| Cosy Courtyard (1 Double Bed) - Package Rate | ROOM ONLY | 2 guests | Free cancellation | ₹56,865 |
| Cosy Courtyard | ROOMONLY | 2 guests | Free cancellation | ₹60,392 |
How much does The Zetter Bloomsbury cost?
Rooms start from ₹56,865 per night on JourneyDeal (live rates vary by date).
Where is The Zetter Bloomsbury located?
It is located in 2-7 Montague Street, London.
Does The Zetter Bloomsbury offer free cancellation?
Yes — free-cancellation rates are available on select room types.